ルート(√)の近似
x(n+1)=(xn/2)+(1/xn)
x(0) = 1 から x(1) = (1/2)+(1/1) x(2) = (3/4)+)(1/3) x(3) = (17/24)+(12/17) x(4) = (577/816)+(408/577)
( x(0) = 3 からも計算可能 )
x(n+1) = (xn/2)+(3/(2*xn))
x(n+1) = (xn/2)+(5/(2*xn))
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